Sharkey/src/mfm/parse.ts
Aya Morisawa 125849673a
Use for-of instead of forEach (#3583)
Co-authored-by: syuilo <syuilotan@yahoo.co.jp>
Co-authored-by: Acid Chicken (硫酸鶏) <root@acid-chicken.com>
2018-12-11 20:36:55 +09:00

41 lines
1.1 KiB
TypeScript

import parser, { Node, plainParser } from './parser';
import * as A from '../prelude/array';
import * as S from '../prelude/string';
export default (source: string, plainText = false): Node[] => {
if (source == null || source == '') {
return null;
}
let nodes: Node[] = plainText ? plainParser.root.tryParse(source) : parser.root.tryParse(source);
const combineText = (es: Node[]): Node =>
({ name: 'text', props: { text: S.concat(es.map(e => e.props.text)) } });
const concatText = (nodes: Node[]): Node[] =>
A.concat(A.groupOn(x => x.name, nodes).map(es =>
es[0].name === 'text' ? [combineText(es)] : es
));
const concatTextRecursive = (es: Node[]): void => {
for (const x of es.filter(x => x.children)) {
x.children = concatText(x.children);
concatTextRecursive(x.children);
}
};
nodes = concatText(nodes);
concatTextRecursive(nodes);
const removeEmptyTextNodes = (nodes: Node[]) => {
for (const n of nodes.filter(n => n.children)) {
n.children = removeEmptyTextNodes(n.children);
}
return nodes.filter(n => !(n.name == 'text' && n.props.text == ''));
};
nodes = removeEmptyTextNodes(nodes);
return nodes;
};